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Rewrite the equation as y-2=-2/3(x-(-1)) to identify a point on the graph

User Horgen
by
4.4k points

2 Answers

2 votes

Answer:

point (-1,2)

Explanation:

User Coddy
by
3.6k points
4 votes

Answer:

point (-1, 2)

Explanation:

Your equation is shown here in point-slope form, so a point on the graph can be read from the given equation. (No further rewrite is necesary.)

The point-slope form is ...

y -k = m(x -h)

Comparing this to your given equation ...

y -2 = (-2/3)(x -(-1))

we see that ...

k = 2, m = -2/3, h = -1

The point on the graph is (h, k) = (-1, 2).

User Subhasish Sahu
by
4.1k points