Question

Find the 96th term of the arithmetic sequence
-3, -14, -25, ...

Answer 1

The 96th term of the given AP is (-1048)

Explanation:

We have, the given AP is :

-3, -14, -25....

First term is -3

Common difference is -14 - (-3)= -11

Let
`a_(96)` is the 96th term of the AP.

The nth term of the AP is given by :

`a_n=a+(n-1)d`

Put all the values, such that,

`a_(96)=(-3)+(96-1)* (-11)\\\\a_(96)=-1048`

So, the 96th term of the given AP is (-1048).