Answer:
He needs to score 100 in his next test.
Explanation:
The average of the exams is given by the sum of each exam score divided by the number of exams he took, therefore his prior average is:
![\text{prior average} = \frac{\text{prior sum of grades}}{\text{prior number of tests}}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/q0xsrv8h21uer7zrlr2cbuc71ps6l6abbd.png)
Since he took five exams and had an average of 88, then his prior sum of grades is:
![\text{prior sum of grades} = 88*5 = 440](https://img.qammunity.org/2021/formulas/mathematics/middle-school/zdwfzxz0e2ayxgxh3l5j2rktpysx288y06.png)
He needs to score "x" in his next test in order to have an 90 average, therefore if we add "x" to the sum of his grades and add 1 to the prior number of tests then equal that to 90, we can solve for "x". We have:
![\text{desired average} = \frac{\text{prior sum of grades} + x}{\text{prior number of texts}+1}\\90 = (440 +x)/(6)\\440 + x = 90*6\\x = 540 - 440\\x = 100\\](https://img.qammunity.org/2021/formulas/mathematics/middle-school/75i3ycf4vee8b29jeac6c2uqn57f7t71gm.png)
He needs to score 100 in his next test.