Question

A circle has a radius of 6/7 units and is centered at (-2.3, 0). Write the equation of this circle.

Answer 1

`(x+2.3)^(2) +y^(2) =36/49`

Explanation:

To get the equation of a circle we plug your information into this equation:

`(x-h)^(2) +(y-k)^(2) =r^(2)`

Your h is the x coordinate of the center, -2.3 and your k is the y coordinate of the center, 0. The r is your radius. So we plug these values in to get
`(x+2.3)^(2) +y^(2) =(6/7)^(2)` which then gives us the final answer of
`(x+2.3)^(2) +y^(2) =36/49`.