Answer:
Explanation:
The hypotenuse is 16 and the adjacent angle is x.
So using SohCahToh
O is opposite, H is the hypotenuse, and A is adjacent.
Soh: sin(theta)= O/H
Cah: cos(theta)= A/H
Toh: tan(theta)= O/A
Any side length that is next to degree 60° is adjacent so x is adjecent.
Using Cah.
cos(theta)= A/H
cos(60°)= x/16
x=16*cos(60°)
x=16*1/2
x=8