Question

Solve the system of equations.

y = x + 3
y = x2 - 2x - 1

A.
(-1, 7) and (4, 2)
B.
(-1, 4) and (4, -1)
C.
(-1, 2) and (4, 7)
D.
(1, 4) and (-4, -1)

Answer 1

Explanation:

x^2 - 2x - 1 = x + 3

x^2 - 3x - 4 = 0

(x - 4)(x + 1)= 0

x - 4 = 0

x = 4

y= 4^2 - 2(4) - 1 = 16-8-1= 8-1= 7

(4, 7)

x + 1 = 0

x = -1

(-1)^2 - 2(-1)-1= 1+2-1=3-1=2

(-1,2)

answer is C

Answer 2

The answer is ( -1, 2) and ( 4,7 )

Explanation: