Answer:
Option (4). 25%
Explanation:
The graph attached shows the exponential growth.
Let the graphed function is y =
Here 'r' = Rate of growth
t = Duration of time in years
y = enrollments after time 't' years
Graph shows at time 't' = 0 or initially number of enrollments = 20
After 8 years number of enrollments will be
120 =
![20(1+(r)/(100))^(8)](https://img.qammunity.org/2021/formulas/mathematics/high-school/wxx4llfcn2ph8cnimg6dfguxm9oixd5qnw.png)
![(120)/(20)=(1+(r)/(100))^(8)](https://img.qammunity.org/2021/formulas/mathematics/high-school/jscudk6incldqnnodskbb6bciynqwjrdbz.png)
6 =
![(1+(r)/(100))^(8)](https://img.qammunity.org/2021/formulas/mathematics/high-school/j9rojxif1ke19qg2lxkyz80ln77us3689u.png)
log 6 =
![8\text{log}(1+(r)/(100))](https://img.qammunity.org/2021/formulas/mathematics/high-school/a53aps2zbm4a63mq4ishylfv3b770a3xpa.png)
0.77815 =
![8\text{log}(1+(r)/(100))](https://img.qammunity.org/2021/formulas/mathematics/high-school/a53aps2zbm4a63mq4ishylfv3b770a3xpa.png)
= 0.0972689
![(1+(r)/(100))=1.251](https://img.qammunity.org/2021/formulas/mathematics/high-school/eirfgo7abj1inqzdxkuco06ewrivoy865d.png)
![(r)/(100)=0.251](https://img.qammunity.org/2021/formulas/mathematics/high-school/eey7vi7cg0kail4v541nm8yhu3xodps89o.png)
r = 25.1%
r ≈ 25%
Therefore, Option (4) will be the answer.