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A 50-kilogram object in outer space is attracted to a nearby planet with a

force of 400 newtons. What is the object's acceleration? *

User Jktress
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1 Answer

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Answer: 8m/s^2

Step-by-step explanation:

By Newton's second law we have that.

F = m*a

Where F is force, m is mass and a is acceleration.

We know that m = 50kg and F = 400N

400N = 50kg*a

a = (400/50) m/s^2 = 8m/s^2

User Rajbir Singh
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