Answer:
(1) 23.55mm³
(2) 340.17in³
Explanation:
Volume of a cone is:
![V=(1)/(3) \pi r^2h](https://img.qammunity.org/2021/formulas/mathematics/middle-school/2ewb3j8hebjdg50bxn9gi0y03ei9tpmhdm.png)
'r' - radius
'h' - height
Cone 1:
The height of Cone 1 is 10 mm. The Diameter of Cone 1 is 3mm.
Radius is half the Diameter.
![3/2=1.5](https://img.qammunity.org/2021/formulas/mathematics/college/w7ukpldvxdwu8d0gfrwmeb2yjd4efti0iw.png)
The radius is 1.5 mm.
![\text {Using 3.14 as pi: }\\V=(1/3)3.14*1.5^2*10\\V=(1/3)3.14*2.25*10\\V=(1/3)70.65\\\boxed{V=23.55}](https://img.qammunity.org/2021/formulas/mathematics/college/l30sktruxajbdp4tbt5vr2vahgy0gnec21.png)
The volume of Cone 1 should be about 23.55mm³.
Cone 2:
The height of Cone 2 is 13 in. The Radius of Cone 2 is 5 in.
Using 3.14 as pi:
![V=(1/3)3.14*5^2*13\\V=(1/3)3.14*25*13\\V=(1/3)1020.5\\\boxed {V=340.166666667}](https://img.qammunity.org/2021/formulas/mathematics/college/toh86advb0qceybnopfketuazhp1a38ey2.png)
340.166666667 ≈ 340.17
The volume of Cone 2 should be about 340.17in³.