Question

please help :( please help :( please help :( please help :( please help :( please help :( please help :( please help :(​

Answer 1

(1) 23.55mm³

(2) 340.17in³

Explanation:

Volume of a cone is:
`V=(1)/(3) \pi r^2h`

'r' - radius

'h' - height

Cone 1:

The height of Cone 1 is 10 mm. The Diameter of Cone 1 is 3mm.

Radius is half the Diameter.

`3/2=1.5`

The radius is 1.5 mm.

`\text {Using 3.14 as pi: }\\V=(1/3)3.14*1.5^2*10\\V=(1/3)3.14*2.25*10\\V=(1/3)70.65\\\boxed{V=23.55}`

The volume of Cone 1 should be about 23.55mm³.

Cone 2:

The height of Cone 2 is 13 in. The Radius of Cone 2 is 5 in.

Using 3.14 as pi:

`V=(1/3)3.14*5^2*13\\V=(1/3)3.14*25*13\\V=(1/3)1020.5\\\boxed {V=340.166666667}`

340.166666667 ≈ 340.17

The volume of Cone 2 should be about 340.17in³.