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Q2: The RMS potential difference of an AC household outlet is 117 v.

a) What is the maximum potential difference across a lamp connected to the outlet?
b) If the RMS current through the lamp is 5.5 A, what is the lamp's maximum current?

User Yutaka
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1 Answer

3 votes

Answer:

(a) 165.46 V

(b) 7.78 A

Step-by-step explanation:

(a) From the question,

Vrms = V₀/√2...................... Equation 1

Where V₀ = maximum potential difference across a lamp connected to the outlet.

make V₀ the subject of the equation.

V₀ = √2(Vrms)............... Equation 2

Given: Vrms = 117 V.

Substitute into equation 2

V₀ = (√2)(117)

V₀ = 165.46 V.

(b) Similarly,

I₀ = √2(Irms)....................... Equation 3

Given: Irms = 5.5 A

Substitute into equation 3

I₀ = (√2)(5.5)

I₀ = 7.78 A.

User Frank Wilson
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