Question

A gas occupies 10.00L at 100k and exerts a pressure of 1.71atm. What volume, in liters, will the gas occupy if the temp is increased to 290.29K and the pressure is increased to 9.70atm?

Answer 1

5.12 L

Step-by-step explanation:

P1V1/T1 = P2V2/T2

1.71 atm *10.0L /100 K = 9.70 atm *x/290.29 K

x = 1.71 atm *10.0L*290.29K /(100 K * 9.70 atm)= 5.12 L