Question

plz help me solve this question. ​

Answer 1

`\frac{\sqrt[3]{95^2}}{17\cdot95^4}=\frac{\sqrt[3]{9\,025}}{1\,384\,660\,625}`

Explanation:

The applicable rules of exponents are ...

(ab)^c = (a^c)(b^c)

(a^b)/(a^c) = a^(b-c)

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`(190^3)/(68^2)*\frac{34}{95^{(19)/(3)}}=((2\cdot 95)^3)/((2\cdot 34)^2)\cdot\frac{34}{95^6\cdot 95^{(1)/(3)}}=2^(3-2)95^{3-6-(1)/(3)}34^(1-2)\\\\=2\cdot 95^{-3(1)/(3)}\cdot 34^(-1)=2\cdot 95^{-4+(2)/(3)}\cdot 34^(-1)\\\\=\frac{2\sqrt[3]{95^2}}{95^4\cdot 34}=\frac{\sqrt[3]{95^2}}{17\cdot95^4}\\\\=\frac{\sqrt[3]{9\,025}}{1\,384\,660\,625}`