Answer:
0.0228
Explanation:
Let us assume that the mean (μ) = 2 and the standard deviation (σ) = 0.5
Z score is a standard score used to measure the number of standard deviations by which the raw score (x) is above or below the mean. It is given by the equation:
![z=(x-\mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/high-school/24k01r9qa0a6ibv4tds8q1jpbjh932http.png)
For x > 3
![z=(x-\mu)/(\sigma) =(3-2)/(0.5)=2](https://img.qammunity.org/2021/formulas/mathematics/high-school/1oe13nvcbnb6wqx5tycp2lnysbrr8g447f.png)
From the normal distribution table, P(x > 3) = P(z > 2) = 1 - P(z < 2) = 1 - 0.9772 = 0.0228