Answer:
13
Explanation:
Let OC = r and OA = r
We can use the Pythagorean theorem to solve sin AB is tangent
a^2 + b^2 = c^2
OA^2 + AB^2 = OB^2
r^2 + 12^2 = (8+r)^2
FOIL
r^2 + 144 = r^2 +16r+64
Subtract r^2 from each side
144 = 16r +64
Subtract 64 from each side
144-64 = 16r
80 = 16r
Divide by 16
80/16 = r
5=r
We want OB
OB = r+8 = 5+8 = 13