Answer:
150 ounces
Explanation:
It is convenient to write an equation for the total amount of alcohol in the mix.
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Let x represent the amount of pure alcohol added. Then the amount of alcohol in the mix is ...
500(35%) +x(100%) = (500 +x)(50%)
x = 500(15%) +x(50%) . . . . . . . subtract 500(35%)
x(50%) = 500(15%) . . . . . . . . . . subtract x(50%)
x = (500)(15%)/(50%) = 150 . . . . divide by the coefficient of x
150 ounces of pure alcohol should be added to produce the desired solution.