Answer:
0 if the original expression is : 3x^2 + 4yz
Explanation:
3x^2 + 4yz ; I guess this is the original expression.
When x=2, y = 1 z =-3
3x^2 + 4yz = 3(2)^2 + 4 × (1)×(-3)
= 3×4 + 4 × (-3) = 12 - 12 = 0
16
3x² + 4y² where x = 2, y = 1, and z = -3
Here we just need to plug in the given values to their respective variables
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