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(8^4)(6^3)(16^-2)÷32

User NMGod
by
4.4k points

2 Answers

5 votes

Answer:

(3/2)^3

Explanation:

The trick here is to identify the common base (it is 2) and express all factors except for 3^2 as powers of 2 that can be added or subtracted.

Note that 8 = 2^3, 6 = 2 * 3, 16 = 2^4 and 32 = 2^5. Using this info, we can immediately begin reducing the given expression:

(2^3)(2^3)(3^3) 2^6*3^3 3^3

(8^4)(6^3)(16^-2)÷32 => ----------------------- = ---------------- = --------------

2^4*2^5 2^9 2^3

= (3/2)^3

User Varnothing
by
4.4k points
6 votes

Answer:

108

Explanation:

8^4 = 4096

6^3 = 216

16^-2 = 0.00390625

4096x216x0.00390625 = 3456

3456/32 = 108

User Bjorninn
by
5.2k points