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(A\B)xC = (AxC)\(BxC) prove this please​

User Manaclan
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Answer

Shown from explanation

Explanation:

Imagine we have a set A and a set B such that set B is contained in set A .

Therefore;

A\B is a mathematical notation in set theory that means;

A\B = A-B it means complement of A

Look at the attachment for a better understanding of the concept.

Therefore:

(A\B) ×C = (A-B) × C = AxC - B× C= AC- BC

Similarly;

(A×C)\(B×C) = (AC)\(BC)= AC - BC from set theory.

Hence, (A\B) ×C =(A×C)\(B×C)

(A\B)xC = (AxC)\(BxC) prove this please​-example-1
User Sebastianb
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