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SpongeBob SquarePants recently met SpongeSusie Roundpants at a dance. SpongeBob is heterozygous for his square shape, but SpongeSusie is homozygous for her round shape. Create a Punnett square to show the possibilities that would result if SpongeBob and SpongeSusie had children. HINT: square shape is dominant. A. List the possible genotypes and phenotypes for their children. B. What are the chances of a child with a square shape? out of or % C. What are the chances of a child with a round shape? out of or ____%

User BillmanH
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2 Answers

3 votes

Answer:

50

Step-by-step explanation:

User Laszlo Valko
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2 votes

Answer:

A. Pp - square pant

pp - round pant

B. 1 out of 2 or 50%

C. 1 out of 2 or 50%

Step-by-step explanation:

Assuming that square pant shape is represented by the allele P, the alternate version (round pant) will be p.

Spongebob's genotype will be Pp since he is heterozygous for his square pant shape.

SpongeSusie's genotype will be pp since she is homozygous for her round pant shape.

Pp x pp

Progeny: 2Pp, 2pp (See the attached image for the Punnet's square)

Possible genotypes and phenotypes of the children:

Pp - Square pant

pp - round pant

Chances of a child with a square shape = 1/2 or 50%

Chances of a child with a round shape = 1/2 or 50%

SpongeBob SquarePants recently met SpongeSusie Roundpants at a dance. SpongeBob is-example-1
User Billda
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