Question

Can some one explain how to do this?

Answer 1

see explanation

Explanation:

Using the tangent and sine ratios in the right triangle EFG

tan60° =
`(opposite)/(adjacent)` =
`(FG)/(EG)` =
`(28)/(EG)` ( multiply both sides by EG )

EG × tan60° = 28 ( divide both sides by tan60° )

EG =
`(28)/(tan60)` ≈ 16.2 in ( to the nearest tenth )

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sin60° =
`(opposite)/(hypotenuse)` =
`(FG)/(EF)` =
`(28)/(EF)` ( multiply both sides by EF )

EF × sin60° = 28 ( divide both sides by sin60° )

EF =
`(28)/(sin60)` ≈ 32.3 in ( to the nearest tenth )