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What is the missing constant term in the perfect sqaure that starts with x^2 - 4x

User Reza Del
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1 Answer

6 votes

Answer:

The expression is; x^2 – 4c + 4

Explanation:

For the expression to be a perfect square, let us say the constant term should be assigned as ⇒ c;

This creates of following expression;

x^2 - 4x + c

In order to be a perfect square, the discriminant needs to be zero ;

( - 4 )^2 - 4 * ( 1 )c = 0 ,

16 – 4c = 0 ,

4c = 16 ,

c = 4 ,

Solution; The expression is, therefore; x^2 – 4c + 4

User Anish Antony
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