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3 votes
Find two consecutive odd integers such that the sum of their squares is 202.

User Littlejedi
by
8.6k points

2 Answers

5 votes

Answer:

9 and 11

Explanation:

(9^2) + (11^2) Simplify the exponents

81 + 121 = 202

User Oyinlade Demola
by
8.4k points
6 votes

Answer:

9 and 11

Explanation:

The squareroot of 202 is 14... so the numbers are both less than 14.

9*9= 81

11*11= 121

121+81= 202

User Shani Goriwal
by
7.8k points

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