Find two consecutive odd integers such that the sum of their squares is 202.

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asked Sep 14, 2021 149k views

3 votes

Find two consecutive odd integers such that the sum of their squares is 202.

Mathematics
college

Littlejedi asked

by Littlejedi

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2 Answers

5 votes

Answer:

9 and 11

Explanation:

(9^2) + (11^2) Simplify the exponents

81 + 121 = 202

Oyinlade Demola answered Sep 15, 2021

by Oyinlade Demola

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6 votes

Answer:

9 and 11

Explanation:

The squareroot of 202 is 14... so the numbers are both less than 14.

9*9= 81

11*11= 121

121+81= 202

Shani Goriwal answered Sep 20, 2021

by Shani Goriwal

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