1 Answer

Abiieez · Answer 1 · 2023-11-03T15:42:47+0000

Answer:

Q2: J. all real numbers.

Q4:
f(3)=-20

Q15:
y=-3x+5

Explanation:

Q2: J. All real numbers.

Range: It can be
$y\geq 1$ .

It can't be
$y\geq 2$ .

Domain: It can't be
$x\geq 1$ because it is going from (-∞,+∞)

Q4:

f(x)=-2x^2+x-5,f(3)=?

Plugin x with 3 into the equation.

$f(3)=-2(3)^2+(3)-5\\f(3)=-2*9+3-5\\f(3)=-18+3-5=-20\\f(3)=-20$

Q15: point-slope form.

y-(y_1)=m(x-x_0) , plugin
(2,-1)=(x_0,y_0) and m=-3

$y-(-1)=-3(x-(2))\\y+1=-3(x-2)\\y+1=-3x+6\\y=-3x+5$

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