Question

6. The mean of 5 consecutive integers is 19. What is the difference between the largest and

the smallest of the 5 integers?​

Answer 1

Explanation:

If the least integer is n, it means the five consecutive integers are:

n,n+1,n+2,n+3,n+4

Summing all integers we have:

n + n+1+n+2+n+3+n+4

=5n+10

The mean of this integers is

5n+10 /5 =19

5n+10=19*5

5n + 10 = 95

5n = 95 - 10

5n =85

n=85/5=17

The smallest of the integer is n= 17

The largest integer is n + 4 =17+4=23

The difference between the least and largest integer would be;

Is 4

The sum of largest integer and the smallest integer is 23 + 17 = 40

Answer 2

4

Explanation:

The integers are

x

x+1

x+2

x+3

x+4

since they are consecutive

The largest is x+4

The smallest is x

Difference is

x+4 -x

4