Question

Solve each triangle. Give angle measures to the nearest degree

and side lengths to the nearest tenth.

please help :( I don't know how to show the work​

Answer 1

1.

AB:

a² + b² = c²

'a' and 'b' are legs, while 'c' is the hypotenuse

3.6² + 5.2² = 12.96 + 27.04

c² = 40

c = √40

c ≈ 6.3

m∠A:

sine, cosine, tangent

soh -
`(opposite)/(hypotenuse)`

cah -
`(adjacent)/(hypotenuse)`

toa -
`(opposite)/(adjacent)`

∠a:

5.2 = opposite

6.3 = hypotenuse

`(5.2)/(6.3)` = 0.825396...

x = sin^-1(0.825396)

x = 55.6 ≈ 56º

∠b:

90º + 56º = 146

180 - 146 = 34º

repeat for the rest of the problems