Answer:
Explanation:
Let x be a random variable representing the number of freshmen that will enter and graduate from the college. This is a binomial distribution since the outcomes are two ways. It is either they graduate or they don't graduate. The probability of success, p = 55/100 = 0.55
The probability of failure, q would be 1 - p = 1 - 0.55 = 0.45
a) We want to determine P(x = 3)
From the binomial distribution table,
P(x = 3) = 0.34
b) A majority would be all 3 and above graduating. From the binomial distribution table,
P(x ≥ 3) = 0.26
c) mean = np
mean = 80 × 0.55 = 44
Standard deviation = √npq
Standard deviation = √80 × 0.55 × 0.45 = 4.45