Question

The average mark of candidates in an aptitude test was 128.5 with a standard deviation of 8.2.Three scores extracted from the test 148,102,152,what is the average of the extracted scores that are extreme values(outlier).​

Answer 1

Explanation:

Hello!

The variable of interest is

X: mark obtained in an aptitude test by a candidate.

This variable has a mean μ= 128.5 and standard deviation σ= 8.2

You have the data of three scores extracted from the pool of aptitude tests taken.

148, 102, 152

The average is calculated as X[bar]= Σx/n= (148+102+152)/3= 134

I hope this helps!