Question

Two forces are applied on a body. One produces a force of 480-N directly forward while the other gives a 513-N force at 32.4-degrees above the forward direction .Find the magnitude and direction(relative to forward direction of the resultant force that these forces exert on the body)​

Answer 1

F = (913.14 , 274.87 )

|F| = 953.61 direction 16.71°

Step-by-step explanation:

To calculate the resultant force you take into account both x and y component of the implied forces:

`\Sigma F_x=480N+513Ncos(32.4\°)=913.14N\\\\\Sigma F_y=513sin(32.4\°)=274.87N`

Thus, the net force over the body is:

`F=(913.14N)\hat{i}+(274.87N)\hat{j}`

Next, you calculate the magnitude of the force:

`F=√((913.14N)+(274.87N)^2)=953.61N`

and the direction is:

`\theta=tan^(-1)((274.14N)/(913.14N))=16.71\°`