Question

Graph the circle (x-3)^2+(y-7)^2=4

Answer 1

The equation is in the form of the equation of the circle. x^2+y^2=r^2. This equation is for the centre, (0,0).

x-3 and y-7 represents the shift in the centre of the circle in the respective axis. Therefore the centre is (3,7). r=2. d=4. So this circle’s centre is at (3,7) with radius 2.