Answer:
S = √(3V/H)
Explanation:
The opposite operation of squaring is taking the square root.
![\boxed{S=\sqrt{(3V)/(H)}}](https://img.qammunity.org/2021/formulas/mathematics/college/tbuirgims8eqv7uwraootd28jju01xz5qg.png)
_____
In the more general sense, the inverse operation for raising to a power is raising to the reciprocal of that power. We know that ...
(a^b)^c = a^(bc)
When we want bc=1, we must have c=1/b.
We know that the denominator of a fractional power is the index of the corresponding root:
![\displaystyle x^(1)/(n)=\sqrt[n]{x}](https://img.qammunity.org/2021/formulas/mathematics/college/9nyv1tfrldzh6moepf5rzzaozu3zxfd18k.png)
For n=2, we don't usually write the index in the root symbol:
![x^{(1)/(2)}=√(x)](https://img.qammunity.org/2021/formulas/mathematics/college/7qbfbn5li8uve1hfxuofw9ixd03tztabye.png)
In the case of this problem, ...
![(S^2)^{(1)/(2)}=\left((3V)/(H)\right)^{(1)/(2)}\\\\S=\sqrt{(3V)/(H)}](https://img.qammunity.org/2021/formulas/mathematics/college/ito10ph8ly33somfcad5pihsxr8c1c1jcj.png)