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Which of the following is false for the hyperbola (x+5)^2/4^2 - (y-2)^2/3^2=1

A)The transverse axis is horizontal
B)one of the foci has coordinates (0,2)
C)One of the vertices is (-10,2)
D)The center is at (-5,2)

User Tiana
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1 Answer

3 votes

Answer:

C)One of the vertices is (-10,2)

Explanation:

Given the hyperbola:
((x+5)^2)/(4^2) -( (y-2)^2)/(3^2) =1

The standard equation for a hyperbola with a horizontal transverse axis is:


((x-h)^2)/(a^2) -( (y-k)^2)/(b^2) =1 where the center is at (h, k).

For our given hyperbola, the center (h,k)=(-5,2)

Now:


c^2=a^2+b^2\\c^2=4^2+3^2\\c^2=25\\c=5

Since the center is at (-5,2), its foci (-c,0) and (c,0) are:

(-5-5,2) and (-5+5,2)= (-10,2) and (0,2)

Similarly, since the center is at (-5,2), its vertices, (-a,0) and (a,0) are:

(-5-4,2) and (-5+4,2)= (−9,2), (−1,2).

Therefore, the odd option is C.

User Pasquale
by
9.0k points
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