Question

A random sample of n 5 4 individuals is selected from a population with m 5 35, and a treatment is administered to each individual in the sample. After treatment, the sample mean is found to be M 5 40.1 with SS 5 48. a. How much difference is there between the mean for the treated sample and the mean for the original population

Answer 1

5.1

Explanation:

Given that:

sample size n = 4

the mean of the original population μ is = 35

and the mean for the sample after treatment M is = 40.1

standard deviation of the sample SS = 48

The difference between the mean for the treated sample and the mean for the original population is therefore calculated as: M - μ

= 40.1 - 35

= 5.1

The standard error of M is =
`(standard \ deviation \ of \ the \ sample)/(√(sample \ size) )`

The standard error of M is =
`(SS)/(√(n) )`

The standard error of M is =
`(48)/(√(4) )`

The standard error of M is =
`(48)/(2 )`

The standard error of M is = 24