Question

There are 0.55 moles of carbon dioxide gas in a 15.0 L container. This container is at a temperature of 300 K. What is the pressure of the gas inside the container? Use 8.31 L*kPa/mol*K for the gas constant.

A.)760 mm Hg\

B.) 271 kPa

C.) 2 atm

D.) 91.4 kPa

Answer 1

`\large \boxed{\text{D.) 91 kPa}}`

Step-by-step explanation:

We can use the Ideal Gas Law — pV = nRT

Data:

V = 15.0 L

n = 0.55 mol

T = 300 K

Calculation:

`\begin{array}{rcl}pV & =& nRT\\p * \text{15.0 L} & = & \text{0.55 mol} * \text{8.31 kPa$\cdot$ L$\cdot$K$^(-1)$mol$^(-1)*$ 300 K}\\15.0p & = & \text{1370 kPa}\\p & = & \textbf{91 kPa}\end{array}\\\text{The pressure in the container is $\large \boxed{\textbf{91 kPa}}$}`