Answer:
The proportion of second lunch students who eat outside is more than that for the first lunch students.
Explanation:
The complete question is:
Points Northlake High School has two lunch periods. Students can eat their lunch in the cafeteria or on an outside patio. About 35% of students who have first lunch eat outside. Compare this with the percentage of second-lunch students who eat outside.
Eat Outside Eat Inside Total
First Lunch 0.19 0.35 0.54
Second Lunch 0.22 0.24 0.46
Total 0.41 0.59 1.00
Solution:
The conditional probability of an event B given that another event A has already occurred is:
![P(B|A)=(P(A\cap B))/(P(A))](https://img.qammunity.org/2021/formulas/mathematics/high-school/6z01cans8nwcwk092raijiok9ckga5s8cg.png)
The probability of students who have second lunch (S) and eat outside (O) is:
P (S ∩ O) = 0.22
The probability of students who have second lunch (S) is:
P (S) = 0.41
Compute the proportion of student who eats outside given they have second lunch as follows:
![P(O|S)=(P(S\cap O))/(P(S))](https://img.qammunity.org/2021/formulas/mathematics/college/yrnphu42q23klqfrq8con7k91bfigss3co.png)
![=(0.22)/(0.41)\\\\=0.536583\\\\\approx 0.54](https://img.qammunity.org/2021/formulas/mathematics/college/u9wxz8725eez3gjjuckn42jwsuci8dxour.png)
The proportion of second lunch students who eat outside is more than that for the first lunch students.