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GUYS I NEED HELP ASAP

A rectangular playground is 40 feet wide. Find the area of this playground, if the fence around it, including the gates, is 200 feet long.

1 Answer

5 votes

Answer:


A=2400ft

Explanation:

A rectangle is a closed planer quadrilateral with four right angles and its opposite sides are the same length. The fence around it including the gates is 200 feet long, so basically they are providing the perimeter of the rectangle. The perimeter of a rectangle is equal to the sum of all its sides. Hence:


Perimeter=w+h+w+h=2w+2h\\\\Where:\\\\w=Width\\h=Height

The ectangular playground is 40 feet wide, so:


w=40ft

Therefore:


Perimeter=2w+2h\\\\200=2(40)+2h\\\\200=80+2h

Solving for h:


2h=200-80\\\\2h=120\\\\h=(120)/(2) \\\\h=60ft

The area of a rectangle is equal to the product of two of its contiguous sides, hence:


A=wh\\\\A=(40)(60)=2400ft

I attached you a picture of the rectangle

GUYS I NEED HELP ASAP A rectangular playground is 40 feet wide. Find the area of this-example-1
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