Answer:
The center of mass move with the velocity of -3.487 m/s.
Step-by-step explanation:
Given values of block A.
Mass of block A, (M1) = 4 kg
Speed of block A, (V1) = 2 m/s
Given values of block B.
Mass of block B, (M2) = 8.4 kg
Speed of block B, (V2) = -6.1 m/s
Below is the formula to find the velocity of center of mass.
![Velocity = (M1V1 + M2V2)/(M1 + M2) \\](https://img.qammunity.org/2021/formulas/physics/college/rmwqzrwm80b3ezpimu9c7ipu5auuh9lp3z.png)
![= (4 * 2 + 8.4 * (-6.1) )/(4 + 8.4) \\](https://img.qammunity.org/2021/formulas/physics/college/g15415mvtbarqar5a99qgricybh7duea07.png)
![= (- 43.24)/(12.4)\\](https://img.qammunity.org/2021/formulas/physics/college/94uwg9ssc9gqbvolymc0ppvsfbvw955qo6.png)
![= - 3.487 m/s](https://img.qammunity.org/2021/formulas/physics/college/lblxxbcsnzwibd6a33gj5beh36t8kn5py3.png)