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X^2-4x+3=0 solutions
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User Tvgemert
by
6.5k points

1 Answer

3 votes

Answer:

x = 3 or x = 1

Explanation:

Solve for x over the real numbers:

x^2 - 4 x + 3 = 0

Subtract 3 from both sides:

x^2 - 4 x = -3

Add 4 to both sides:

x^2 - 4 x + 4 = 1

Write the left hand side as a square:

(x - 2)^2 = 1

Take the square root of both sides:

x - 2 = 1 or x - 2 = -1

Add 2 to both sides:

x = 3 or x - 2 = -1

Add 2 to both sides:

Answer: x = 3 or x = 1

User Alitosuner
by
7.4k points
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