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Determine the number of solutions for systems x+y=2 and 2x+2y=8

User Markwatson
by
5.6k points

1 Answer

3 votes

Answer:

no solutions

Explanation:

x+y=2

2x+2y=8

Multiply the first equation by -2

-2x -2y = -4

Add this to the second equation

-2x -2y = -4

2x+2y=8

--------------------

0x+0y = 4

0=4

This is never true

so there are no solutions

User Fvrab
by
6.4k points