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Un golfista logra un hoyo tres segundos después de que la pelota fue golpeada. Si la pelota viajó con una rapidez promedio de 0,8 [m/s], ¿cuán lejos se encontraba el hoyo?

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Answer:

Step-by-step explanation:

Question in English

A golfer achieves a hole three seconds after the ball was hit. If the ball traveled with an average speed of 0.8 [m / s], how far was the hole?

Given Data

time, t = 3s

average speed r = 0.8 \frac{m}{s}

d =?

By Kinematics of the MU Uniform Movement

Now we find the distance

d = rt


d = (0.8(m)/(s))(3s)


d=2.4m

Therefore, the answer is 2.4m

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