Question

Which is the equation of a line that has a slope of -2/3 and passes through point (-3,-1)

Answer 1

y = -2/3 x - 3

Explanation:

since you have a point and a slope, you can use point - slope form

`y - y_(1) = m (x - x_(1) )` plug in the point as
`(x_(1), y_(1))` and the slope as m

y - (-1) = -2/3(x - (-3)) change two negatives into positive

y + 1 = -2/3 (x+3) distribute the -2/3

y + 1 = -2/3x - 2 subtract 1 from both sides

y = -2/3 x -3

Answer 2

y = -2/3x - 3

Explanation:

y = mx + b

m = slope

(-3,-1) = (x,y)

Plus in the coordinates

-1 = -2/3(-3) + b

negative times negative = positive

-2/3 * -3 = 2

-1 = 2 +b

Use inverse operations

-2 --2

-3 = b

y = -2/3x - 3