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(2 + 7)2 + (y + 8)2 =
What is its center?

1 Answer

2 votes

Answer:

The center is at ( -7,-8)

Explanation:

The equation of a circle can be written as

(x-h)^2 + (y-k)^2 = r^2

where (h,k) is the center

( x+7) ^2 + (y+8)^2

( x - -7) ^2 + ( y - -8)^2

The center is at ( -7,-8)

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