Question

Plz Wegnerkolmp2741o help me

Answer 1

D. a = -1/5, a = 7/6

Explanation:

Move the variable to the left-hand side and change its sign

`30a^(2) -7-29a=0`

Use the commutative property to reorder the terms

`30a^(2) -29a-7=0`

Write -29a as a difference

`30a^(2) +6a-35a-7=0`

Factor out "6a" and "-7" from the expression

`6x(a)x(5a+1)-35a-7=0`

`6x(a)x(5a+1)-7(5a+1)=0`

Factor out "5a + 1" from the expression

`(5a+1)x(6a-7)=0`

When the product of factors equals 0, at least one factor is 0

`5a+1=0\\6a-7=0`

Solve the equation for a

`a = -(1)/(5)`

`a = (7)/(6)`

The equation has 2 solutions

`a= -(1)/(5) , a=(7)/(6)`

Answer 2

a = 7/6 a = -1/5

Explanation:

30 a^2 - 7 = 29a

Subtract 29a from each side

30 a^2 -29a- 7 = 29a-29a

30 a^2 -29a- 7 = 0

Factor

( -7 ) ( +1) =0 to get -7

We need to determine what goes in the first part

5*7 = 35 - 6 = 29

( 6a -7 ) ( 5a +1) =0

Using the zero product property

6a -7 =0 5a+1 =0

6a = 7 5a = -1

a = 7/6 a = -1/5