Answer:
Vertex is (3,-1) zeros ( 4,0) (2,0) and y intercept (0,8)
Explanation:
y = x^2 - 6x+8
Factor
y = (x-4) (x-2)
Set = 0 to find the zeros
0 = (x-4) (x-2)
Using the zero product property
x-4 = 0 x-2 =0
x=4 x=2
The vertex is 1/2 way between the zeros
(4+2)/2 = 6/2 = 3
y = (3-4) (3-2)
-1 (1)
y = -1
Vertex is (3,-1)
The y intercept is at x=0
y = 0-0+8
y =8