Question

The graph of which inequality has open circles on -16 and 4 with a line segment between them?

o 1 x + 6l<10
o 1 x + 101<-6
o 1 x<6
O 1 X+6 >10
help pls lol

Answer 1

Answer: Choice A.
`|x+6| < 10`

Step-by-step explanation:

The rule is that stuff of the form
`|x| < k` becomes
`-k < x < k` where k is some positive number.

So we'll have these steps

`|x+6| < 10\\\\-10 < x+6 < 10\\\\-10-6 < x+6-6 < 10-6\\\\-16 < x < 4\\\\`

In the third step, I subtracted 6 from all sides to isolate x.

The last step indicates we'll have open holes at -16 and 4, with shading in between. It visually tells the reader "x can be anything between -16 and 4, but can't be equal to either endpoint".