Question

In triangle DOC, cos(D) = 20/29. What is the value of tan(D)?

Answer 1

`tan(D) = (21)/(20)`

Explanation:

Step(i):-

Given in triangle DOC

Cos(D) = 20/29

now

`Sec(D) = (1)/(Cos(D)) = (1)/((20)/(29) ) = (29)/(20)`

We Know that trigonometry formulas

`sec^(2)(D) -tan^(2) (D) =1`

`tan^(2) (D) = sec^(2) (D) -1`

=
`((29)/(20) )^(2) -1`

=
`(841 -400)/(400) = (441)/(400)`

`tan^2(D) = (441)/(400)`

`tan(D) = \sqrt{(441)/(400) } = (21)/(20)`

`tan(D) = (21)/(20)`