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In triangle DOC, cos(D) = 20/29. What is the value of tan(D)?

1 Answer

1 vote

Answer:


tan(D) = (21)/(20)

Explanation:

Step(i):-

Given in triangle DOC

Cos(D) = 20/29

now


Sec(D) = (1)/(Cos(D)) = (1)/((20)/(29) ) = (29)/(20)

We Know that trigonometry formulas


sec^(2)(D) -tan^(2) (D) =1


tan^(2) (D) = sec^(2) (D) -1

=
((29)/(20) )^(2) -1

=
(841 -400)/(400) = (441)/(400)


tan^2(D) = (441)/(400)


tan(D) = \sqrt{(441)/(400) } = (21)/(20)


tan(D) = (21)/(20)

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