Answer:
![3m/s^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/br2kw5m8cu17tb5hh1l5f77pkqtyzbsi0n.png)
Explanation:
the information that we have is:
mass:
![m=20kg](https://img.qammunity.org/2021/formulas/mathematics/high-school/3siytneglwwdv6ia4hmqr33krckqzqlomv.png)
force applied:
![F=60N](https://img.qammunity.org/2021/formulas/mathematics/high-school/7fxucv6u8z1i038e8vbo4v05zfge6l34wd.png)
since we need to find the acceleration, we can use Newton's second law of motion:
![F=ma](https://img.qammunity.org/2021/formulas/physics/college/kxqi3lxi3fjfv761qhdu0s1p00agxd9vve.png)
Where
is the force applied to a mass
which creates an acceleration
.
we solve this equation for the acceleration:
![a=(F)/(m)](https://img.qammunity.org/2021/formulas/physics/college/v2lw8t7zggbatliop5ra41qcfea299q4rb.png)
and we substitute the known values:
![a=(60N)/(20kg) \\\\a=3m/s^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/u4zjh8b8rfivwbei647omf1v9pqd40o1nr.png)
the acceleration of the load is:
![3m/s^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/br2kw5m8cu17tb5hh1l5f77pkqtyzbsi0n.png)