Answer:
The rate of heat transfer between pipe and its surrounding is found to be 1250 KW
Step-by-step explanation:
Assuming no significant change in potential energy. When we apply the first law of thermodynamics to the given system of 1-D pipe, we get the following expression:
Q = m(h₁ - h₂)
where,
Q = Heat Transfer between pipe and surrounding = ?
m = mass flow rate of steam = 0.5 kg/sec
h₁ = Specific Enthalpy of steam at entrance = 4000 KJ/kg
h₂ = Specific Enthalpy of steam at exit = 1500 KJ/kg
Therefore, using these values in the equation, we get the value of heat transfer:
Q = (0.5 kg/sec)(4000 KJ/kg - 1500 KJ/kg)
Q = 1250 KW