Question

In ΔDEF, d = 410 cm, e = 300 cm and ∠F=126°. Find the length of f, to the nearest centimeter.

Answer 1

634.6 cm

Explanation:

f^2 = d^2 + e^2 - 2(d)(e)cos(angle)

f^2 = (410)^2 + (300)^2 - 2(410)(300)cos(126)

f^2 = 402695 and take the square root

Answer 2

635

Explanation: