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The coordinates below are the endpoints of the diameter.

Find the coordinates of the center


Find the length of the radius.



Write the equation of the circle standard form.

1 Answer

5 votes

Answer:


(x+1)^(2) +(y+0.5)^(2) =5.3^(2)

Explanation:

The endpoints of the diameter are (-5,3) and (3,-4).

We know that the mid point of the diameter is the center of the circle, and half of its length is the radius. Let's find the center first.


C=((-5+3)/(2) ,(3-4)/(2) )\\C=((-2)/(2) ,(-1)/(2) )\\C=(-1, -0.5)

The length of the diameter can be found with the formula below


d=\sqrt{(y_(2) -y_(1) )^(2)+(x_(2) -x_(1) )^(2) } \\d=\sqrt{(-4-3)^(2) +(3-(-5))^(2) } =√(49+64)\\ d=√(113) \approx 10.6

Therefore, the diameter is 10.6 units, approximately.

So, the radius is


r=(d)/(2) \approx (10.6)/(2)=5.3

Therefore, the radius is 5.3 units.

Now we can find the equation of the circle


(x+1)^(2) +(y+0.5)^(2) =5.3^(2)

User Florentino
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