Question

How much heat will be absorbed by 122 g of water when its temperature is raised by 17oC? The specific heat for water is 4.18 J/g oC. Use significant figures.

Answer 1

`Q=8669.3J=8.67kJ`

Step-by-step explanation:

Hello,

In this case, we can compute the absorbed heat of water needed to raise its temperature by 17 °C by using the following formula:

`Q=mCp\Delta T`

In this case, the mass is 122 g, the specific heat 4.18 J/(g°C) and the temperature change 17 °C, hence the heat turns out:

`Q=122g*4.18(J)/(g\°C)*17\°C\\ \\Q=8669.3J=8.67kJ`

Best regards.

Answer 2

Heat energy = 8669.32J

Step-by-step explanation:

Mass = 122g

Change in temperature ∇T = 17°C

Specific heat capacity (c) = 4.18J/g°C

Heat energy (Q) = ?

Heat energy (Q) = mc∇T

Q = heat energy

M = mass of the substance

C = specific heat capacity of the substance

∇T = change in temperature of the substance

Q = mc∇T

Q = 122 × 4.18 × 17

Q = 8669.32J

The heat energy required to raise 122g of water by 17°C is 8669.32J